Re: The problem of relativistic synchronisation

Den 05.09.2024 16:15, skrev Richard Hachel:

Le 05/09/2024 à 14:24, "Paul.B.Andersen" a écrit :

Den 05.09.2024 01:23, skrev Richard Hachel:

We KNOW that the travel time of A in A'B' will be equal to the distance A'B' in R' divided by the apparent escape velocity of an object moving at v=0.8c. >>>
Vo=0.8c
>
Vapp=Vo/(1+cosµ.Vo/c)
>
Vapp'=(4/9)c
>
Vapp"=4c
>
R.H.

What do you say, Paul?

How confused is it possible to be? 😂
You must know that this 'apparent speed' is a visual
observation (telescope).
 From whence did you get the idiotic idea that somebody
is visually observing any of the clocks in this paper?
https://paulba.no/pdf/Mutual_time_dilation.pdf
A  and B  are moving with the speed v = 0.8c in K'  <-
A' and B' are moving with the speed v = 0.8c in K   ->
Nothing is moving with any other speed than v.
There are no 'apparent speeds'.
Is this too hard for you to understand?
--
Paul
https://paulba.no/