Re: [SR] Their proper times will necessarily be equal

W dniu 13.04.2024 o 18:37, gharnagel pisze:

Richard Hachel wrote:

>
"If two different observers travel an identical path in equal observable times,

 "Observable"?
WHO is doing the observing?  Presumably, an observer at earth, yes?
 

then their proper times will necessarily be equal.

 This is not possible.
 

  Let's set up a Galilean frame of reference, in which a Galilean mobile moves from left to right on the x axis.
>
  When it goes to O, in R, we click.
>
  When it passes x, let's say 12 al, we click.
>
  For example, we obtain To=12.915.
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  Or a speed of Vo=x/To=0.9291c
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  Tr=To.sqrt(1-Vo²/c²)=4.776

 This is assuming a constant velocity of v = 0.9291c, yes.  The proper time
of the trip is 4.7746 years, using c = 299792458 m/s and one year equal to
3600*24*365.25 = 31557600 seconds.

AAnd in the meantime in the real world, forbidden
by your bunch of idiots "improper" clocks keep
measuring t'=t, just like all serious clocks
always did.