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Le 24/07/2024 à 20:44, "Paul.B.Andersen" a écrit :Den 24.07.2024 15:08, skrev Richard Hachel>
Now what does the global ring look like in the proton frame of reference, and above all what is the trajectory of point A during one revolution?
To the very slow reader R.H:Irrelevant.
The point A is at any instant adjacent to the proton.
We consider an arbitrary instant I.
Let K(x,t) be an inertial frame of reference which at the instant I
is momentarily comoving with the point A.
The speed of the proton in K is v = dx/dt = L/T = 0.999999991·c
Do you know another definition of the speed of the proton in K
than dx/dt ?
Let K'(x',τ) be an inertial frame of reference which at the instant I
is momentarily comoving with the proton.
The speed of the point A in K' is v' = dx'/dτ = (L/γ)/τ = 0.999999991·c
Do you know another definition of the speed of the point A in K'
than dx'/dτ ?
It's not a joke, it's a question.And your point is?
We take a very large particle accelerator of several kilometers.
On this particle accelerator, we fix a point A, coordinates (0,0,0) and we ask to draw the trajectory of the proton in R.
We assume z=0.
We then have a large circle.
We then request a change of reference frame, and we request the trajectory of point A in the proton reference frame.
I wish good luck to whoever answers, it's not high school level.
R.H.
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