Re: The problem of relativistic synchronisation

Le 01/09/2024 à 22:29, M.D. Richard "Hachel" Lengrand a écrit :

Le 01/09/2024 à 19:41, "Paul.B.Andersen" a écrit :

Den 01.09.2024 16:13, skrev Richard Hachel:

 

AB (at rest) = 3.10^8m
A'B' (at rest) = 3.10^8m
>
v=0.8c tA(e2)= ?

 

tA(e2)=0.75 sec

 

Chicken!

 No YOU chicken !
 tA (e1)= 0

If you insist, but this in no way a requisite of Einstein-Poincaré's
synchronization procedure. t_A = 451 is another possible value :-)

tA'(e1)= 0

LOL!!! Whaaat the Hell is that???

tA (e2)= 0.75

Irrelevant. The time marked by clock A "when" B received the first
signal is undefined at that time (i.e. "when" is undefined for remote
events). It does play any role in the procedure. Fortunately.
Le poulet piteux Lengrand est tout déplumé :-)