Re: The problem of relativistic synchronisation

Den 02.09.2024 01:39, skrev Python:

Le 01/09/2024 à 22:29, M.D. Richard "Hachel" Lengrand a écrit :

tA (e1)= 0

 If you insist, but this in no way a requisite of Einstein-Poincaré's
synchronization procedure. t_A = 451 is another possible value :-)
 

tA'(e1)= 0

 LOL!!! Whaaat the Hell is that???
 

tA (e2)= 0.75

 Irrelevant. The time marked by clock A "when" B received the first
signal is undefined at that time (i.e. "when" is undefined for remote
events). It does play any role in the procedure. Fortunately.
 

You are misunderstanding.
Richard never quote what he is responding to, so the context
is lost.
This is not about Einstein's synchronisation method,
but about this paper:
https://paulba.no/pdf/Mutual_time_dilation.pdf
tA(e1) = 0
tA'(e1)= 0
by definition
With Richards (unrealistic as always) numbers:
c ≈ 3e8 m/s
d = 3e8 m
v = 0.8c
tA(e2) = (d/v)⋅√(1−v²/c²) ≈ 0.75 seconds
--
Paul
https://paulba.no/