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Am Dienstag000024, 24.09.2024 um 22:43 schrieb Richard Hachel:I've told you already: you can name yourLe 24/09/2024 à 22:08, Python a écrit :This hyperplane of the present is always perpendicular to the axis of time and time is a local measure.>>
Quite the opposite. They don't need hints to know you are talking
shit. By the way you should (you won't) think about the comparison
with a siren on an ambulance going forth and back. I'll post about
this soon, but you may want to find by yourself.
The sound Doppler effect is interesting, but well... Once again, you're going to waste your time.
You're going to show that the Doppler effect explanation works, and nothing more: you're not going to get to the bottom of things.
But you're not going to show why it works, because you take my equations for total crap, despite their logic and mathematical beauty that even Einstein or Poincaré didn't have.
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But FUCK, that's not what's important, it's not your watermelon that's going to synchronize the watches, it's not your ambulance siren, but we don't care about all that.
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That's not the important thing.
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The important thing is to understand that the notion of a relativistic frame of reference is biased if we apply it to anything other than the observer himself.
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The important thing is to understand that since each observer has his own relativistic hyperplane of simultaneity, it is mandatory to go through it to correctly and perfectly describe things.
'perpendicular' means here (in a complex plane) a multiplication by i (the sqrt(-1)).
So time is an imaginary (pseudo-) scalar, if you regard the axes x, y and z as real.
If we place the observer in the center of the coordinate system, the axis of local time becomes perpendicular to the hyperplane of the present.
This is valid for all observers everywhere.
From this would follow, that time MUST be local and is not always 'parallel'.
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