Re: A discussion of 'Tachyons, the 4-momentum ...'

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Sujet : Re: A discussion of 'Tachyons, the 4-momentum ...'
De : r.hachel (at) *nospam* liscati.fr.invalid (Richard Hachel)
Groupes : sci.physics.relativity
Date : 03. Oct 2024, 13:36:27
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Organisation : Nemoweb
Message-ID : <j3f1ccBcOPWkaLCVw-N3SGdc830@jntp>
References : 1
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Le 03/10/2024 à 12:10, hitlong@yahoo.com (gharnagel) a écrit :
In DOI: 10.13189/ujpa.2023.170101, Figure 4 depicts a thought
experiment involving FTL communication.  This figure is
attached to this post.  We, the viewers, are at rest with
observers A and B.
 At event E1, observer A, at x = 0, t = vL/c^2, sends an
infinitely-fast tachyon signal to observer B, who receives
it at x = L, t = vL/c^2.  B immediately passes it to D, who
is moving at velocity v.  D's clock reads t' = 0.
 D is now going to send it to C.  The question is, where is
C?  Is C at x = 0 or is C at x = Lv^2/c^2?  According to
us (the viewers), C is at x = Lv^2/c^2, but if we (the
viewers) switched frames so we're at rest with C and D,
(see Figure 5 in DOI: 10.13189/ujpa.2023.170101).  Now,
it appears that D can send a signal to c at t' = t = 0
(infinitely-fast).
 But according to our (the viewers) present position in
Figure 5, A (at t = 0) could only send the original signal
to B, who would receive it at t = vL/c^2, or the loop
would not be completed (because of the relativity of
simultaneity).
 Let's move back to Figure 4.  So in order to complete
the loop, D must send the signal to where C is not (at
t = 0, x = 0), which flouts RoS.  But at t = vL/c^2, C
is not adjacent to A, so no closed loop can be completed
in this scenario.
 Comments, Prok?
What must be understood in special relativity is that the photon IS already a tachyon since it moves infinitely fast; since it IS an instantaneous energy transaction in the hyperplane of simultaneity of the receiver.
There is a lack of understanding of generalized RR that makes even the biggest experts no longer understand anything about it and worse, probably start laughing when they read interesting and decoding stuff like: "photons go much faster than the speed of light". This seems FORCEFULLY absurd to them.
They do not understand what Dr. Hachel says, which is in fact: "Photons are instantaneous transactions in the hyperplane
of the receiver (which is the photon extractor from the source) but which seems to move at c, in the hyperplane of the neutral observer placed at an equal distance from the source and the receiver.
R.H.
Date Sujet#  Auteur
3 Oct 24 * A discussion of 'Tachyons, the 4-momentum ...'13gharnagel
3 Oct 24 +- Re: A discussion of 'Tachyons, the 4-momentum ...'1Maciej Wozniak
3 Oct 24 +* Re: A discussion of 'Tachyons, the 4-momentum ...'7Richard Hachel
3 Oct 24 i`* Re: A discussion of 'Tachyons, the 4-momentum ...'6gharnagel
3 Oct 24 i `* Re: A discussion of 'Tachyons, the 4-momentum ...'5Richard Hachel
4 Oct 24 i  `* Re: A discussion of 'Tachyons, the 4-momentum ...'4gharnagel
4 Oct 24 i   `* Re: A discussion of 'Tachyons, the 4-momentum ...'3Richard Hachel
4 Oct 24 i    `* Re: A discussion of 'Tachyons, the 4-momentum ...'2gharnagel
4 Oct 24 i     `- Re: A discussion of 'Tachyons, the 4-momentum ...'1Richard Hachel
5 Oct 24 `* Re: A discussion of 'Tachyons, the 4-momentum ...'4gharnagel
5 Oct 24  `* Re: A discussion of 'Tachyons, the 4-momentum ...'3Richard Hachel
6 Oct 24   `* Re: A discussion of 'Tachyons, the 4-momentum ...'2Python
6 Oct 24    `- Re: A discussion of 'Tachyons, the 4-momentum ...'1Maciej Wozniak

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