Sujet : Re: How can gravity itself escape a black hole?
De : hitlong (at) *nospam* yahoo.com (gharnagel)
Groupes : sci.physics.relativityDate : 01. Nov 2024, 14:14:43
Autres entêtes
Organisation : novaBBS
Message-ID : <97dfb8e00846bea7e0b4b2b75bb47330@www.novabbs.com>
References : 1 2 3 4
User-Agent : Rocksolid Light
On Fri, 1 Nov 2024 11:12:51 +0000, kazu wrote:
>
its not about flowing, at the event horizon, the object is
accelerated to c and as a result time stops.
>
from your perspective, you are looking at all the mass as it was
in the past, but from the masses' perspective, it has already
crossed the horizon.
It's irrelevant to us what the mass sees since we're too smart
to fall into a BH. What we see is
dtau^2/dt^2 = 1 - rs/r - vt^2/c^2 - (vr^2/c^2)/(1 - rs/r)
So if the mass is falling straight in, v-tangential = 0, but
what about v-radial? We assume vr will reach c, but will it?
It appears that dtau/dt will reach zero BEFORE the mass reaches
the Schwarzschild radius because of the last term, so time
freezes from our perspective before the mass reaches rs.
What that point is depends on the mass trajectory initial
conditions.
Consider the case when vr = 0 and vt^2/c^2 = rs/2r. The mass
is in orbit around the BH at r = 1.5rs and time is frozen from
the distant observer's perspective, which is strange: how can
it orbit if it's frozen ...
Anyway, that mass would see the rate of time in all the rest of
the universe speeding up until, at the critical point, the mass
would have seen the end of the universe, which is equivalent for
distant observers to see time stopping for the mass.