Re: Relativistic synchronisation method

Le 17/12/2024 à 11:45, Richard Hachel  a écrit :
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As for his method of synchronization, it is just two lines to explain that tA'-tA=2AB/c (which is true) and therefore that tB-tA=tA'-tB=AB/c but by omitting to say WHO takes the measurement of that, that is to say by believing that it is everyone.

Not at all. There is NO ambiguity. tA and t'A are measured by clock A (for events that happen there), tB is measured by clock B (for an event that happens there too).
And, obvisously, the fact that "clock X measure tX for an event happening there" is the same fact for everyone. Only fools of your kind can pretend that 1 + 1 = 3 for some observers.