Re: Relativistic synchronisation method

Le 17/12/2024 à 18:32, Python a écrit :

 2. Tu travestis ma pensée en me faisant dire ce que je n'ai pas dit. Je n'ai jamais dit que ce que marquait une montre lors d'un événement conjoint était relatif par changement d'observateur.

 It is your words : "but by omitting to say WHO takes the measurement of that".
 There is no admission : an observer at A measures time shown on clock A for two events, an observer at B measures time shown on another clock at another event.
 Clocks can show any values, nothing is supposed than they tick at the same rate.

But both evolve at the same rate!
Otherwise it's absurd.
Breathe, blow...
I'll start again (breathe, blow, it's going to be okay, the good doctor Hachel is here).
Watch A and watch B are in the same inertial frame of reference.
They are stationary.
Simply separated by a distance x=AB=3.10^8m.
There is no reason why they should not beat at the same rate.
Which translates also means "they have the same chronotropy" or their internal mechanism beats at the same rate, and there is no reason to imagine any internal Doppler effect between them.
R.H.