Re: Relativistic synchronisation method

Le 17/12/2024 à 18:50, Richard Hachel  a écrit :
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Similarly, the duration e(3)-(e1) will be the same for all observers in the frame of reference, it is only for observers placed in other frames of reference that the duration will be modified, since the chronotropy is modified there, and that, moreover, the return of the signal is not in the same place, which leads to a double correction.

The duration between event e3 and e1 is not involved in the procedure. As a matter of fact it cannot even be known at that stage. Only tA, t'A and tB are know. PERIOD.

But that's not what I'm talking about,

Neither do I.

I'm talking about the fact that if we practice a type M synchronization,

There is no such thing as "M" in the procedure. Stop making up stuff.

the events will not take place at the same time on the other observer's watch.

Nothing of that kind is involved in the procedure. As a matter of fact such an expression does not even make sense at that stage.

[snip more diversion]

Dying of laughter...

You'd better die of shame.

In short, "they still haven't understood the principle".

In short, you haven't still understand the procedure. Even with an application showing it in practice.

It's sad.

That you are un incurable idiot, liar and hypocrite. Sure.