Re: Einstein cheated with his fraudulent derivation of Lorentz transforms

Den 08.02.2025 21:14, skrev rhertz:

On Sat, 8 Feb 2025 19:54:58 +0000, Paul.B.Andersen wrote:
 

>
I have now read your attachment, and I didn't panic.

Your "graphics":

I was however mildly shocked by the extent of your confusion.
>
What I found was this:
  Δτ₁ = x'/(c-v)
  Δτ₂ = x'/(c-v)+x'/(c+v)
  τ₁ = τ₀ + Δτ₁
  τ₂ = τ₀ + Δτ₂
>
I won't bother to yet again explain why this is nonsense,
because you are unable to learn.
>

I have read your "graphics"!
Do you still not understand why I called it nonsense ? :-D

 If you can't read posts correctly in your Eternal August, try this site
with a browser.
 Maybe you'll be able to observed my last posts and graphics and
enter in reason. But I doubt it.

 I REPEAT MY LATEST POST, IN CASE YOU MISSED IT, ASSHOLE!
 From: rhertz
 Newsgroups: sci.physics.relativity
Date: Sat, 8 Feb 2025 14:03
 ******************************************************************
Asked to Google:
 What is x' in Einstein's derivation of Lorentz transforms?
 Answer from Google AI (which is a resume of many documents):
 -------------------------------------------------------------------
 

The AI did obviously not understand your question.

AI Overview
 In Einstein's derivation of the Lorentz transformations, "x'" represents
the position of an event as measured in a moving reference frame
(denoted as S'), while "x" represents the position of the same event in
a stationary reference frame (S); essentially, it's the transformed
x-coordinate in the moving frame, taking into account the relative
velocity between the two frames.
Key points about x':
 Relative to x:
"x'" is related to "x" through the Lorentz transformation equation,
which includes the relative velocity (v) between the reference frames
and the Lorentz factor (γ).

Did you find this remarkable?
The frames of reference the AI refers to are obviously:
The "stationary system": S(x,t)
The "moving system":     S'(x',t')
As the AI says:
"x'" is related to "x" through the Lorentz transformation:
  x' = (x - vt)/√(1−v²/c²)

 Interpretation:
If an event occurs at position "x" in the stationary frame, "x'"
indicates where that same event would be observed in the moving frame.

Right. (But a bit awkwardly put.)
If the coordinates of an event are (x,t) in S,
then the coordinates of the same event are (x',t') in S'
where:
   x' = (x - vt)/√(1−v²/c²)
   t' = (t - vx/c²)/√(1−v²/c²)
That's why it is called a _coordinate_ transformation.
Did you have a point with quoting the AI's trivial answer?

 -------------------------------------------------------------------
 Also: Galilean transform in Einstein's paper:
 http://hyperphysics.phy-astr.gsu.edu/hbase/Relativ/ltrans.html

The Galilean transform in a webpage from HyperPhysics,
Georgia State University, is Hardly
"Galilean transform in Einstein's paper".
There is no Galilean transform in Einstein's 1905 paper.
Did you have a point with this reference?

-------------------------------------------------------------------
NOW, WHAT ABOUT THIS PAPER?
 Einstein’s Derivation of the Lorentz Transformations
in the1905 Paper is Internally Inconsistent
 Jon C. Freeman
 https://www.nikhef.nl/~h02/deriv_lt_freeman.pdf

Have a look at some of the 6341 other "Research Papers" in
"the general science Journal":
https://www.gsjournal.net/Science-Journals-Papers/Type/Research%20Papers
.. and you will understand why Freeman chose to publish his paper in
    that particular journal.
--
Paul
https://paulba.no/