Sujet : Re: Positrons
De : relativity (at) *nospam* paulba.no (Paul.B.Andersen)
Groupes : sci.physics.relativityDate : 08. Jul 2025, 20:38:08
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Den 08.07.2025 16:17, skrev Stefan Ram:
"Paul.B.Andersen" <relativity@paulba.no> wrote or quoted:
Den 08.07.2025 00:02, skrev Stefan Ram:
"Paul.B.Andersen" <relativity@paulba.no> wrote or quoted:
e⁺ + e⁻ → γ + γ
Energy and momentum are preserved.
The energy equivalence of an electron and a positron is 0.511 MeV,
so the energy of each of the gamma particles is 0.511 MeV. (0.024 Å)
(Mass is converted to pure kinetic energy of photons)
Mass is /not/ changed in this process when the mass of the system
"γ + γ" is being compared with the mass of the system "e⁺ + e⁻".
Why would you consider γ + γ as a closed system?
Well, I was talking about a "system", not a "closed system".
Many people go with
E^2 = (mc^2)^2 + (pc)^2
and emphasize that energy and momentum are conserved in a process
"-->", while mass can be converted into "pure kinetic energy".
Now, let's call the values before a process (left of the arrow "-->")
"0" and those after the process (right of the arror "-->") "1".
Then, what the people say would be:
E_1 = E_0 "Energy is conserved"
p_1 = p_0 "momentum is conserved"
m_1 < m_0 "mass is converted into energy"
Please explain why these three assumptions are not compatible with:
e⁺ + e⁻ → γ + γ
But these three assumptions are not compatible with
E_0^2 = (m_0c^2)^2 + (p_0c)^2 and
E_1^2 = (m_1c^2)^2 + (p_1c)^2
!
Let the mass of the leptons be m.
Let the speed of the leptons be equal v in opposite directions.
γ = 1/√(1 − v²/c²)
For Each of the leptons we get: (E₀/2)² = (mc²)² + (γmvc)²
E₀² = 4(mc²)² + 4(γmvc)²
The momentum for each of the gamma particles is p = E₀/2c
E₁/2 = pc = E₀/2
E₁² = E₀² = 4(mc²)² + 4(γmvc)²
E₁ = E₀ "Energy is conserved"
-------------------
Since both the leptons and the gamma particles are moving
with the same speed in opposite direction, the net momentum
is zero both before and after annihilation.
p₁ = E₀/2c - E₀/2c = 0 p₀ = γmv - γmv = 0
p₁ = p₀ "momentum is conserved"
----------------------
m₀ = 2m, m₁ = 0
m₁ < m₀ "mass is converted into energy"
------------------------------
-- Paulhttps://paulba.no/