Mike can't even count to eight --- HHH(DDD)

On 6/10/2025 11:09 AM, Mike Terry wrote:

On 10/06/2025 12:41, Mikko wrote:

On 2025-06-10 00:47:12 +0000, olcott said:
>

On 6/9/2025 7:26 PM, Richard Damon wrote:

On 6/9/25 10:43 AM, olcott wrote:

On 6/9/2025 5:31 AM, Fred. Zwarts wrote:

Op 09.jun.2025 om 06:15 schreef olcott:

On 6/8/2025 10:42 PM, dbush wrote:

On 6/8/2025 11:39 PM, olcott wrote:

On 6/8/2025 10:32 PM, dbush wrote:

On 6/8/2025 11:16 PM, olcott wrote:

On 6/8/2025 10:08 PM, dbush wrote:

On 6/8/2025 10:50 PM, olcott wrote:

void DDD()
{
   HHH(DDD);
   return;
}
>
The *input* to simulating termination analyzer HHH(DDD)

>
No it's not, as halt deciders / termination analyzers work with algorithms,

>
That is stupidly counter-factual.
>

>
That you think that shows that

>
My understanding is deeper than yours.
No decider ever takes any algorithm as its input.

>
But they take a description/specification of an algorithm,

>
There you go.
>

which is what is meant in this context.

>
It turns out that this detail makes a big difference.
>

And because your HHH does not work with the description/ specification of an algorithm, by your own admission, you're not working on the halting problem.
>

>
HHH(DDD) takes a finite string of x86 instructions
that specify that HHH simulates itself simulating DDD.

>
And HHH fails to see the specification of the x86 instructions. It aborts before it can see how the program ends.
>

>
This is merely a lack of sufficient technical competence
on your part. It is a verified fact that unless the outer
HHH aborts its simulation of DDD that DDD simulated by HHH
the directly executed DDD() and the directly executed HHH()
would never stop running. That you cannot directly see this
is merely your own lack of sufficient technical competence.

>
And it is a verified fact that you just ignore that if HHH does in fact abort its simulation of DDD and return 0, then the behavior of the input, PER THE ACTUAL DEFINITIONS, is to Halt, and thus HHH is just incorrect.
>

>
void DDD()
{
   HHH(DDD);
   return;
}
>
How the f-ck does DDD correctly simulated by HHH
reach its own "return" statement final halt state?

>
If HHH is not a decider the question is not interesting.
If HHH is a deider it returns. The first insturunction
after the return terminates the execution of DDD.

 But then DDD *simulated by HHH* does is not simulated as far as its own return statement.  In fact zero steps of DDD are simulated.
 

Since I have shown you the execution trace of DDD simulated
by HHH many times it is gross negligence that you say that
"zero steps of DDD are simulated."
_DDD()
[00002172] 55         push ebp      ; housekeeping
[00002173] 8bec       mov ebp,esp   ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404     add esp,+04
[00002182] 5d         pop ebp
[00002183] c3         ret
Size in bytes:(0018) [00002183]
_main()
[00002192] 55         push ebp
[00002193] 8bec       mov ebp,esp
[00002195] 6872210000 push 00002172 ; push DDD
[0000219a] e833f4ffff call 000015d2 ; call HHH(DDD)
[0000219f] 83c404     add esp,+04
[000021a2] 50         push eax
[000021a3] 6843070000 push 00000743
[000021a8] e8b5e5ffff call 00000762
[000021ad] 83c408     add esp,+08
[000021b0] 33c0       xor eax,eax
[000021b2] 5d         pop ebp
[000021b3] c3         ret
Size in bytes:(0034) [000021b3]
  machine   stack     stack     machine    assembly
  address   address   data      code       language
  ========  ========  ========  =========  =============
[00002192][00103820][00000000] 55         push ebp      ; Begin main()
[00002193][00103820][00000000] 8bec       mov ebp,esp   ; housekeeping
[00002195][0010381c][00002172] 6872210000 push 00002172 ; push DDD
[0000219a][00103818][0000219f] e833f4ffff call 000015d2 ; call HHH(DDD)
New slave_stack at:1038c4
Begin Local Halt Decider Simulation   Execution Trace Stored at:1138cc
[00002172][001138bc][001138c0] 55         push ebp      ; housekeeping
[00002173][001138bc][001138c0] 8bec       mov ebp,esp   ; housekeeping
[00002175][001138b8][00002172] 6872210000 push 00002172 ; push DDD
[0000217a][001138b4][0000217f] e853f4ffff call 000015d2 ; call HHH(DDD)
New slave_stack at:14e2ec
[00002172][0015e2e4][0015e2e8] 55         push ebp      ; housekeeping
[00002173][0015e2e4][0015e2e8] 8bec       mov ebp,esp   ; housekeeping
[00002175][0015e2e0][00002172] 6872210000 push 00002172 ; push DDD
[0000217a][0015e2dc][0000217f] e853f4ffff call 000015d2 ; call HHH(DDD)
Local Halt Decider: Infinite Recursion Detected Simulation Stopped
[0000219f][00103820][00000000] 83c404     add esp,+04
[000021a2][0010381c][00000000] 50         push eax
[000021a3][00103818][00000743] 6843070000 push 00000743
[000021a8][00103818][00000743] e8b5e5ffff call 00000762
Input_Halts = 0
[000021ad][00103820][00000000] 83c408     add esp,+08
[000021b0][00103820][00000000] 33c0       xor eax,eax
[000021b2][00103824][00000018] 5d         pop ebp
[000021b3][00103828][00000000] c3         ret
Number of Instructions Executed(10069) == 150 Pages

Of course, DDD directly executed will reach its own return statement, so it is true that this DDD halts...
 

Likewise if you twin brother robbed a liquor store
this make you yourself guilty because you look the
same as him.

 Mike.
 

--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer