Sujet : Re: ChatGPT totally understands exactly how I refuted the conventional halting problem proof technique
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theory sci.logic comp.ai.philosophyDate : 24. Jun 2025, 22:41:37
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <103f62i$292tp$1@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
User-Agent : Mozilla Thunderbird
On 6/24/2025 4:07 PM, joes wrote:
Am Tue, 24 Jun 2025 13:06:22 -0500 schrieb olcott:
On 6/24/2025 12:57 PM, joes wrote:
Am Tue, 24 Jun 2025 12:46:01 -0500 schrieb olcott:
>
It is an easily verified fact that no *input* to any partial halt
decider (PHD) can possibly do the opposite of what its corresponding
PHD decides. In all of the years of all of these proofs no such
*input* was ever presented.
>
You should clarify that you don't even think programs can be passed as
input.
>
It is common knowledge the no Turing Machine can take another directly
executed Turing Machine as an input.
So common that nobody would suggest such. You are the king of strawmen.
*From the bottom of page 319 has been adapted to this*
https://www.liarparadox.org/Peter_Linz_HP_317-320.pdfWhen Ĥ is applied to ⟨Ĥ⟩
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.∞
if Ĥ applied to ⟨Ĥ⟩ halts
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
if Ĥ applied to ⟨Ĥ⟩ does not halt
Ĥ applied to ⟨Ĥ⟩ does not have embedded_H reporting on
the behavior specified by its input ⟨Ĥ⟩ ⟨Ĥ⟩ it has embedded_H
reporting on its own behavior.
Since Turing Machines cannot take directly executing
Turing Machines as inputs this means that the directly
executed Ĥ applied to ⟨Ĥ⟩ is not in the domain of
Ĥ.embedded_H, *thus no contradiction is ever formed*
-- Copyright 2025 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer