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On 7/13/2024 8:15 AM, Richard Damon wrote:No, because it has been shown that EVERY DDD instance that is based on ANY of the HHHs that abort their emulation and return will also reach past that address and return. It is only the PARTIAL EMULATION of them by HHH which does not and that is NOT a "correct emulation" per the x86 language as it breaks the "and the next instruction will execute rule"On 7/13/24 7:39 AM, olcott wrote:You switch from disagreeing with the x86 language to disagreeingOn 7/13/2024 3:15 AM, Fred. Zwarts wrote:>>>
This is double talk, because no HHH can possibly exist that simulates itself correctly.
Your definition of correct contradicts the semantics of
the x86 language making it wrong.
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No your ideas of the x86 language contradicts the actual sematic of the language.
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Where does it ever even imply that a partial emulation correctly predicts the behavior of the full program?
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that all deciders must halt.
*This proves that every rebuttal is wrong somewhere*
No DDD instance of each HHH/DDD pair of the infinite set of
every HHH/DDD pair ever reaches past its own machine address of
0000216b and halts thus proving that every HHH is correct to
reject its input DDD as non-halting.
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