Re: Everyone on this forum besides Keith has been a damned liar about this point

On 6/8/2025 10:50 PM, olcott wrote:

void DDD()
{
   HHH(DDD);
   return;
}
 The *input* to simulating termination analyzer HHH(DDD)

No it's not, as halt deciders / termination analyzers work with algorithms, but you HHH does not by your own admission:
On 5/13/2025 9:54 PM, dbush wrote:
 > On 5/13/2025 9:48 PM, olcott wrote:
 >> On 5/13/2025 8:31 PM, dbush wrote:
 >>> On 5/13/2025 9:27 PM, olcott wrote:
 >>>> On 5/13/2025 8:07 PM, dbush wrote:
 >>>>> On 5/13/2025 5:30 PM, olcott wrote:
 >>>>>> On 5/13/2025 6:43 AM, Richard Damon wrote:
 >>>>>>> On 5/13/25 12:52 AM, olcott wrote:
 >>>>>>>> *simulated D would never stop running unless aborted*
 >>>>>>>> or they themselves could become non-terminating.
 >>>>>>>
 >>>>>>> But you aren't simulating the same PROGRAM D that the original
 >>>>>>> was given.
 >>>>>>>
 >>>>>>
 >>>>>> It is not supposed to be the same program.
 >>>>>
 >>>>> So you *explicitly* admit to changing the input.
 >>>>>
 >>>>
 >>>> The finite string of DD is specific sequence bytes.
 >>>
 >>> Which includes the specific sequence of bytes that is the finite
 >>> string HHH
 >>>
 >>
 >> No it does not. A function calls is not macro inclusion.
 >>
 >
 > Then you admit that your HHH not deciding about algorithms and therefore
 > has nothing to do with the halting problem.
 >
On 6/7/2025 10:56 AM, dbush wrote:
 > On 6/7/2025 10:54 AM, olcott wrote:
 >> On 6/7/2025 9:51 AM, dbush wrote:
 >>> On 6/7/2025 10:32 AM, olcott wrote:
 >>>> The next instruction of DDD that HHH emulates is at
 >>>> the machine address of 00002183.
 >>>>
 >>>> The next instruction of DDD that HHH1 emulates is at
 >>>> the machine address of 00002190.
 >>>
 >>> False.
 >>>
 >>> The next instruction of DDD that both HHH and HHH1 emulates is at the
 >>> machine address of 000015c3,
 >>
 >> *That is not an instruction of DDD*
 >> *That is not an instruction of DDD*
 >> *That is not an instruction of DDD*
 >> *That is not an instruction of DDD*
 >
 > In other words, you're not operating on algorithms.  And since the
 > halting problem is about algorithms, what you're working on has nothing
 > to do with the halting problem.
 >
 > If you would just be honest about the fact that you're not working on
 > the halting problem, people would stop bothering you.