Sujet : Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary)
De : wolfgang.mueckenheim (at) *nospam* tha.de (WM)
Groupes : sci.mathDate : 28. Nov 2024, 21:20:10
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <viaj9q$l91n$1@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
User-Agent : Mozilla Thunderbird
On 28.11.2024 20:28, FromTheRafters wrote:
WM used his keyboard to write :
On 28.11.2024 17:45, joes wrote:
Am Thu, 28 Nov 2024 11:39:05 +0100 schrieb WM:
>
A simpler arguments is this: All endsegments are in a decreasing
sequence.
There is no decrease, they are all infinite.
>
Every endsegment has one number less than its predecessor.
That is called decrease.
More like the subset relation. It is not a decrease in cardinality.
Of course not. Cardinality is nothing else than infinitely many.
But as long as infinitely many natnumbers have not left the endsegments, they stay inside all of them. And many are the same for all endsegments. Therefore the intersection of infinite endsegments is infinite.
Regards, WM
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