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On 8/6/24 4:35 AM, WM wrote:
Peano is not valid for all dark numbers.Right. But with NUF(x) = 1 ==> INVNUF(1) = x we getBut INVNUF(1) can't exist, as it will be bigger than
∃u ∈ ⅟ℕ, u < x, ∀y > x = INVNUF(1).
1/ ( ceil(1/INVNUF(1)) +1 ), and 1/ ( ceil(1/INVNUF(1)) +2 )
which are two different unit fractions.
Regards, WM
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