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Am 06.08.2024 um 00:19 schrieb Jim Burns:But with NUF(x) = k ==> INVNUF(k) = x we getOn 8/5/2024 3:04 PM, WM wrote:Huh?!For every number of unit fractions
NUF(x) gives the smallest interval (0, x).
IIRC: NUF(x) := |{u ∈ ⅟ℕ : u < x}| (x e IR)
Hence NUF(x) does NOT "give the smallest interval (0, x)", but the (cardinal) number of (the set of) unit fractions which are smaller than x (with x e IR).
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