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On 8/6/2024 4:35 AM, WM wrote:
NUF(x) ≠ 1∀n ∈ ℕ: 1/n - 1/(n+1) > 0 implies its existence.
is true everywhere
NUF(x) = 1 ⇒ INVNUF(1) = x
is true everywhere
However,
its truth doesn't imply INVNUF(1) exists.
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