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Le 07/08/2024 à 20:49, Jim Burns a écrit :On 8/7/2024 9:05 AM, WM wrote:Le 07/08/2024 à 04:36, Richard Damon a écrit :On 8/6/24 4:35 AM, WM wrote:
If darkᵂᴹ numbers exist,>>>Right. But with NUF(x) = 1 ==> INVNUF(1) = x we get>
∃u ∈ ⅟ℕ, u < x, ∀y > x = INVNUF(1).
But INVNUF(1) can't exist, as it will be bigger than
1/ ( ceil(1/INVNUF(1)) +1 ), and 1/ ( ceil(1/INVNUF(1)) +2 )
which are two different unit fractions.
Peano is not valid for all dark numbers.
For each real x > 0
there are ℵ₀.many visibleᵂᴹ unit.fractions
between x and 0
For each visible real.
>There is no real x > 0 such that>
there are fewer than ℵ₀.many visibleᵂᴹ unit fractions
between x and 0
They exist but are dark.
∀ᴿx>0: NUFᵛⁱˢ(x) = ℵ₀Darkᵂᴹ numbers do not make _fewer_ visibleᵂᴹ numbers,>
do they?
No.
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