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Le 10/08/2024 à 19:28, Jim Burns a écrit :On 8/10/2024 11:54 AM, WM wrote:Le 09/08/2024 à 02:32, Jim Burns a écrit :
<place for argument>Surely, a lawyer wouldn't think that>
"Boom! Here's the conclusion"
is an _argument_ ?
∀n ∈ ℕ: 1/n - 1/(n+1) > 0
If an interval contains unit fractions,<place for argument>
then it contains a first one.
>Therefore>
there can only be a single first unit fraction.
No one has said there are two first unit.fractions.
What forbids zero first unit.fractions?
The existence of unit frations enforces
one or more first unit fractions.
>What causes an exception: nₓ ∈ ℕ without ⅟(nₓ+1) ?>
The end of the positivee axis.
∀n ∈ ℕ: 1/n > 1/(n+1) > 0∀n ∈ ℕ: 1/n - 1/(n+1) > 0
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