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Am 13.08.2024 um 19:02 schrieb Jim Burns:Numbers can be seen.On 8/13/2024 10:21 AM, WM wrote:Le 12/08/2024 à 19:44, Jim Burns a écrit :No number can be seen, dark or not.There is no ⅟nₓ before the end of the positive axis>
without ⅟(nₓ+1) before the end of the positive axis.
You cannot see it. It is dark.
Therefore 1/(n0 + 1) does not exist.Assume NUF(x0) = 1 with x0 e IR. This means that there is exactly one unit fraction u such that u < x0. Let's call this unit fraction u0. Then (by definition) there is a (actually exactly one) natural number n such that u0 = 1/n. Let n0 e IN such that u0 = 1/n0. But then (again by definition) 1/(n0 + 1) is a unit fraction which is smaller than u0 and hence smaller than x0. Hence NUF(x0) > 1. Contradiction!resulting in a real coordinate x with NUF(x) = 1.
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