Sujet : Re: Replacement of Cardinality
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.logic sci.mathDate : 15. Aug 2024, 17:16:06
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <9ef8dd8a-69be-44e2-bcf6-ea9c1fb30e21@att.net>
References : 1 2 3 4 5 6 7 8 9 10 11
User-Agent : Mozilla Thunderbird
On 8/15/2024 9:52 AM, WM wrote:
Le 14/08/2024 à 18:43, Jim Burns a écrit :
On 8/14/2024 8:23 AM, WM wrote:
Therefore there is no step at 0.
>
There is a step at 0.
>
Nonsense.
⎛ Assume otherwise.
⎜ Assume NUF(x) = 0 and x > 0
⎜
⎜ β ≥ x > 0 for
⎜ β greatest.lower.bound of unit.fractionsᵈᵉᶠ
⎜ 2⋅β > β ⇒ not.lower.bound 2⋅β
⎜ ½⋅β < β ⇒ lower.bound ½⋅β
⎜
⎜ 2⋅β > ⅟k ⇐ not.lower.bound 2⋅β
⎜ ¼⋅2⋅β > ¼⋅⅟k
⎜ ¼⋅2⋅β = ½⋅β
⎜ ½⋅β > ¼⋅⅟k ⇒ not.lower.bound ½⋅β
⎜
⎜ lower.bound ½⋅β and not.lower.bound ½⋅β
⎝ Contradiction.
However,
0 is not a unit.fractionᵈᵉᶠ.
>
Therefore there is no step.
NUF(x) steps only at unit fractions x.
If NUF(x) doesn't step at 0
then lower.bound ½⋅β and not.lower.bound ½⋅β