Re: Replacement of Cardinality

Le 24/08/2024 à 19:06, Richard Damon a écrit :

On 8/23/24 10:49 AM, WM wrote:

NUF(x) increases from 0 to more. But it  cannot increase by more than 1 without shzowing a constant level.
 

And, since there is no finite value of x that makes NUF(x) equal to 1, since for every finite x, their exists an x/2

For all visisble x but not for all dark x.

Just because you have verbally defined a function doesn't mean it exists and has proper values.

This function exists because nothing contradicts its existence.
Regards, WM