Re: Replacement of Cardinality

Le 27/08/2024 à 02:06, Jim Burns a écrit :

On 8/25/2024 3:45 PM, WM wrote:

This function exists because
nothing contradicts its existence.

 Except for the contradicting consequences of
its existence.

The function exists if actual infinity exists.
The function does not exist if only potential infinity exists.

¬∃ᴿx>0: NUF(x) = 1

Then NUF(x) does not exist and infinity is not actual and sets are not complete.
Regards, WM