Re: Replacement of Cardinality

On 8/27/24 3:11 PM, WM wrote:

Le 27/08/2024 à 02:06, Jim Burns a écrit :

On 8/25/2024 3:45 PM, WM wrote:

 

This function exists because
nothing contradicts its existence.

>
Except for the contradicting consequences of
its existence.

 The function exists if actual infinity exists.
The function does not exist if only potential infinity exists.
 

¬∃ᴿx>0: NUF(x) = 1

 Then NUF(x) does not exist and infinity is not actual and sets are not complete.
 Regards, WM
 

Well NUF(x) does not exist, but that doesn't say that infiity is not actual, or that sets are not complete, just that your logic can't handle it.
Your IGNORANCE doesn't prove that something can't exist for people who can actually think.