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On 8/27/24 3:11 PM, WM wrote:Do you think that people who see thatLe 27/08/2024 à 02:06, Jim Burns a écrit :>On 8/25/2024 3:45 PM, WM wrote:>>This function exists because>
nothing contradicts its existence.
Except for the contradicting consequences of
its existence.
The function exists if actual infinity exists.
The function does not exist if only potential infinity exists.
>¬∃ᴿx>0: NUF(x) = 1>
Then NUF(x) does not exist and infinity is not actual and sets are not
complete.
>
Regards, WM
>
>
Well NUF(x) does not exist, but that doesn't say that infiity is not
actual, or that sets are not complete, just that your logic can't handle
it.
>
Your IGNORANCE doesn't prove that something can't exist for people who
can actually think.
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