Sujet : Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary)
De : richard (at) *nospam* damon-family.org (Richard Damon)
Groupes : sci.logicDate : 15. Dec 2024, 22:14:02
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <67e587a384538d7d311613630232bf025415e67b@i2pn2.org>
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User-Agent : Mozilla Thunderbird
On 12/15/24 2:44 PM, WM wrote:
On 15.12.2024 13:54, Richard Damon wrote:
>
You can't "name" your dark numbers,
because they are dark.
You already admitted that the set of definable natural numbers was in fact the set of all natural numbers,
No.
> so there is nothing left to be dark
|ℕ \ {1, 2, 3, ...}| = 0 cannot be accomplished by visible numbers because ∀n ∈ ℕ_def: |ℕ \ {1, 2, 3, ..., n}| = ℵo.
Regards, WM
Which just shows that the full set in infinte, and any member in it is finite, and not the last member.
Your logic is just based on false assumptions, errors, and lies.
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