Sujet : Re: Replacement of Cardinality (ubiquitous ordinals)
De : ross.a.finlayson (at) *nospam* gmail.com (Ross Finlayson)
Groupes : sci.logic sci.mathDate : 02. Aug 2024, 20:55:16
Autres entêtes
Message-ID : <Ah2cnYogF_UTpDD7nZ2dnZfqnPGdnZ2d@giganews.com>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
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On 08/02/2024 03:39 AM, FromTheRafters wrote:
Ross Finlayson explained on 8/1/2024 :
On 08/01/2024 05:36 PM, Jim Burns wrote:
On 8/1/2024 3:28 PM, Ross Finlayson wrote:
On 08/01/2024 04:23 AM, Jim Burns wrote:
On 7/31/2024 8:30 PM, Ross Finlayson wrote:
On 07/31/2024 01:21 PM, Jim Burns wrote:
>
If I remember correctly, your (RF's) name for
not.talking about
what's outside the domain of discussion
is hypocrisyᴿꟳ.
>
That sounds like you're delivering a value.judgment:
that we _should not_ not.talk about
what's outside the domain of discussion,
that we _should not_ for example, not.talk about
_all_ triangles when we discuss whether
the square of its longest side equals
the sum of the squares of the two remaining sides.
>
Yeah, my mathematical conscience demands that
hypocrisy is bad.
>
Bad why?
>
"Wrong", ....
>
It is wrong to treat claims about right triangles
as though they are claims about more than right triangles.
>
Definition usually expands,
>
The hypocrisyᴿꟳ of NOT expanding
the definition of right triangle ABC
to encompass triangles without right angles
leaves it NOT wrong that
a segment CH from right angle C
perpendicular to and meeting side AB at H
makes two more triangles ACH BCH,
which are both similar to ABC
which, as similar triangles,
have corresponding sides in the same ratio
so that
A͞H/A͞C = A͞C/A͞B
H͞B/B͞C = B͞C/A͞B
(A͞H+H͞B)⋅A͞B = A͞C² +B͞C²
and
A͞B² = A͞C² + B͞C² is NOT wrong.
>
hypocrisy is bad.
>
If it is, then it isn't for making things wrong,
which is something hypocrisyᴿꟳ
(not.talking about outside the domain)
doesn't do.
>
>
>
There is no "outside" the universe.
>
Then what *is* restricted comprehension?
Usually it's just the antonym of expansion of comprehension.
What I ask,
if that you surpass,
the inductive impasse,
of the infinite super-task.