Re: Replacement of Cardinality

Am 06.08.2024 um 22:21 schrieb Chris M. Thomasson:

On 8/6/2024 6:33 AM, Moebius wrote:

Am 06.08.2024 um 04:24 schrieb Chris M. Thomasson:
>

There are infinite[ly many] even[ numbers] and
there are infinite[ly many] odd[ numbers].

>
On the other hand, some even numbers are odd. :-)

 ;^D 666?
 Ahh zero. I think its even... ;^)
 1, 2, 3, 4, ...
 odd, even, odd, even, ...
 So, the pattern:
 -2, -1, 0, 1, 2
 even, odd, (even), odd, even

Yes. An integer z is even, iff there is am integer k such that z = 2k.
Clearly for z = 0 there is an integer k (namely 0) such that z = 2k.
In other words, an integer z is even if it can be deviede by 2 "without a remainder =/= 0".
Clearly 0 can be devided by 2 "without a remainder =/= 0": 0 / 2 = 0.
So 0 is an odd even number? :-)