Re: Replacement of Cardinality

On 8/6/2024 2:02 PM, Moebius wrote:

Am 06.08.2024 um 22:21 schrieb Chris M. Thomasson:

On 8/6/2024 6:33 AM, Moebius wrote:

Am 06.08.2024 um 04:24 schrieb Chris M. Thomasson:
>

There are infinite[ly many] even[ numbers] and
there are infinite[ly many] odd[ numbers].

>
On the other hand, some even numbers are odd. :-)

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;^D 666?
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Ahh zero. I think its even... ;^)
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1, 2, 3, 4, ...
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odd, even, odd, even, ...
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So, the pattern:
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-2, -1, 0, 1, 2
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even, odd, (even), odd, even

 Yes. An integer z is even, iff there is am integer k such that z = 2k.
 Clearly for z = 0 there is an integer k (namely 0) such that z = 2k.
 In other words, an integer z is even if it can be deviede by 2 "without a remainder =/= 0".
 Clearly 0 can be devided by 2 "without a remainder =/= 0": 0 / 2 = 0.
 So 0 is an odd even number? :-)

I say even? Well, both (odd and even) at the same time? This makes me think of signed zero...
+0
-0
and just, 0?
(-2)->(-1)->(-0+)->(+1)->(+2)
? ;^)
so going from -2, -1, -0 means we got to zero from the negative side.
+2, +1, +0 means we got to zero from the positive side.
0 is just zero?
-0+ ? wtf! ;^)