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On 8/19/2024 1:17 PM, Moebius wrote:0 is the greatest lower bound because every greater number can be undercut by a visible unit fraction.Am 19.08.2024 um 18:58 schrieb Jim Burns:No positive point is a lower.bound of[...]>
You got it totally wrong!
>
The dark unit fractions are smaller than
the (all) visible ones.
all the visibleᵂᴹ unit.fractions. (lemma)
Each darkᵂᴹ unit.fraction is a positive point.
No darkᵂᴹ unit.fraction is a lower.bound of
all the visibleᵂᴹ unit.fractions.
No darkᵂᴹ unit.fraction is smaller than
all the visibleᵂᴹ unit.fractions.
----
Lemma.
No positive point is a lower.bound (lb) of
all the visibleᵂᴹ unit.fractions.
⎛ Assume 0 < lb.⅟ℕᵈᵉᶠ ≤ glb.⅟ℕᵈᵉᶠ = β
⎜ not.bound 2⋅β > ⅟k ∈ ⅟ℕᵈᵉᶠ
⎜ not.bound ½⋅β > ¼⋅⅟k ∈ ⅟ℕᵈᵉᶠ
⎜ bound ½⋅β < β
⎝ Contradiction.
¬(lb.⅟ℕᵈᵉᶠ > 0)
Now:More than that.
The visible unit fraction don't have
a smallest one (of course),
The visibleᵂᴹ unit fractions don't have
a positive lower bound.
WM has not quite conceded that.
The last I've seen, he omits 'greatest'.
If he ever does, it is game over.
With or without his concession,Dark unit fractions cannot be defined. The GLB that can be defined is 0.
there is no positive lower bound of
visibleᵂᴹ unit fractions, and
there is no darkᵂᴹ unit.fraction.
Impossible. Lower bounds must be definable.WM: "Dark unit fractions have a smallest element."WM says a lot of things.
If dark unit.fractions are positive lower bounds of
visible unit fractions,
then they don't exist,The function NUF(x) grows by 1 at every unit fraction. It starts from 0.
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