Re: HHH(DDD) is correct to reject its input as non-halting --- EVIDENCE THAT I AM CORRECT

On 6/16/2025 6:28 AM, Richard Damon wrote:

On 6/15/25 8:57 PM, olcott wrote:

On 6/15/2025 6:44 PM, Richard Damon wrote:

On 6/15/25 4:10 PM, olcott wrote:

void DDD()
{
   HHH(DDD);
   return;
}
>
When I challenge anyone to show the details of exactly
how DDD correctly simulated by ANY simulating termination
analyzer HHH can possibly reach its own simulated "return"
statement final halt state they ignore this challenge.

>
And it seems you don't understand that the problem is that while, yes, if HHH does infact do a correct simulation, it will not reach a final state, that fact only applie *IF* HHH does that, and all the other HHHs which differ see different inputs.
>

>
*I should have said*
When one or more instructions of DDD are correctly
simulated by ANY simulating termination analyzer HHH
then DDD never reaches its simulated "return" statement
final halt state.
>

 So?
 Since that isn't the criteria that the decider is supposed to answer by, it is just a strawman.
 

*You merely dishonestly changed the subject*
Whenever I challenge anyone to provide the details to show
exactly how the below (a) & (b) is not true they ignore this
challenge and change the subject.
   (a) One of more instructions of DDD are correctly
   simulated by some simulating termination analyzer HHH.
   (b) None of the above simulated DDD instances ever
   reach its own simulated "return" statement final halt state.
Whenever I challenge anyone to provide the details to show
exactly how the above (a) & (b) is not true they ignore this
challenge and change the subject.
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer