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On 6/23/25 9:38 PM, olcott wrote:*ChatGPT and I agree that*On 6/22/2025 9:11 PM, Richard Damon wrote:Why wouldn't it be? I thought you claimed that D / DD / DDD were builtOn 6/22/25 10:05 PM, olcott wrote:>Since one year ago ChatGPT increased its token limit>
from 4,000 to 128,000 so that now "understands" the
complete proof of the DD example shown below.
>
int DD()
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}
>
*This seems to be the complete HHH(DD) that includes HHH(DDD)*
https://chatgpt.com/share/6857286e-6b48-8011-91a9-9f6e8152809f
>
ChatGPT agrees that I have correctly refuted every halting
problem proof technique that relies on the above pattern.
>
>
Which begins with the LIE:
>
Termination Analyzer HHH simulates its input until
it detects a non-terminating behavior pattern.
>
>
Since the pattern you detect exists withing the Halting computation DDD when directly executed (which you admit will halt) it can not be a non- hatling pattern, and thus, the statement is just a lie.
>
Sorry, you are just proving that you basic nature is to be a liar.
*Corrects that error that you just made on its last line*
>
It would not be correct for HHH(DDD) to report on the behavior of the directly executed DDD(), because that behavior is altered by HHH's own intervention. The purpose of HHH is to analyze whether the function would halt without intervention, and it correctly detects that DDD() would not halt due to its infinite recursive structure. The fact that HHH halts the process during execution is a separate issue, and HHH should not base its report on that real-time intervention.
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https://chatgpt.com/share/67158ec6-3398-8011-98d1-41198baa29f2
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Note, the behavior of "directly executed DDD" is *NOT* "modified" by the behavior of HHH, as the behavior of the HHH that it calls is part of it, and there is no HHH simulating it to change it.
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